Question

Find the number of moles in 3.10 x 10^-1g of boron

Answer 1

0.0286 moles

Step-by-step explanation:

Given mass,
`m=3.1* 10^(-1)g=0.31\ g`

Molar mass of boron, M = 10.811 g/mol

`\text{No of moles}=\frac{\text{given mass}}{\text{molar mass}}\\\\n=(0.31)/(10.811 )\\\\n=0.0286`

Hence, there are 0.0286 moles in given mass of boron.