Question

Solve the equation: x^2 + 8x = 0

Answer 1

x²+8x=0

⇒a=1 b=8 c=0

Δ=b²-4ac

Δ=8²-4.1.0

Δ=8²

Now you solve the bhaskara formula:

x=-b±
`\sqrt{}`Δ/2a

x=-8±8/2

x1=0

x2= -8

hope this helps.