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In the reaction MgCl2 + 2KOH → Mg(OH)2 + 2KCI, how many moles of KOH

react with 1 mole of MgCl2?

asked
User Klaudio
by
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2 Answers

6 votes

Answer:

2 moles of KOH

3 votes

Answer:

2 moles of KOH are required.

Step-by-step explanation:

Given data:

Moles of MgCl₂ = 1 mol

Number of moles of KOH react with MgCl₂ = ?

Solution:

Chemical equation:

MgCl₂ + KOH → Mg(OH)₂ + KCl

Balanced chemical equation:

MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl

From balance chemical equation it can be seen when one mole of MgCl₂ react then 2 moles of KOH are required. It means double quantity of KOH is react with MgCl₂ in order to produced one mole of Mg(OH)₂ and 2 moles of KCl.

The above reaction also completely follow the la of conservation mas mass because there are equal number of atoms of reactant and products on both side of chemical equation.

answered
User Alpert
by
8.0k points
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