Question

Three times the greater of two consecutive odd integers is five less than four

times the smaller. Find the two numbers.
A. 11, 13
15, 17
C.
8, 10
D. 8,9

Answer 1

A

Explanation:

Let the smallest integer (odd) be 2x + 1

Let the larger of the integers be 2x + 3

3*(2x + 3) = 4(2x + 1) - 5 remove the brackets

6x + 9 = 8x + 4 - 5 Combine

6x + 9 = 8x - 1 Add 1 to both sides

6x + 9 + 1 = 8x Combine

6x + 10 = 8x Subtract 6x

10 = 2x Divide by 2

10/2 = x

x = 5

So the smaller odd number is 2x + 1 = 2*5 + 1 = 11

And the larger off number = 2x + 3 = 2*5 + 3 = 13