A circle in the xy-plane is represented by the equation (x-4)^2+(y-4)^2=c, where c is a constant. If (0, 0) is a point on this circle, what is the value of c?

Question

A circle in the xy-plane is represented by the equation
`(x-4)^2+(y-4)^2=c`, where
`c` is a constant. If (0, 0) is a point on this circle, what is the value of
`c`?

Answer 1

32 = c

Explanation:

We are given the point (0, 0). This means that is what we will substitute for x and y.

(x - 4)² + (y - 4)² = c

(0 - 4)² + (0 - 4)² = c

-4² - 4² = c

16 + 16 = c

32 = c

Best of Luck!

Answer 2

• c = 32

Explanation:

Given the equation of circle:

• (x - 4)² + (y - 4)² = c

And the point on same circle (0, 0)

Finding the value of c by considering the coordinates of the given point in the equation

• (x - 4)² + (y - 4)² = c
• (0 - 4)² + (0 - 4)² = c
• ( -4)² + (- 4)² = c
• 16 + 16 = c
• 32 = c
• c = 32