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Given f(t) = 3 r3 - 3r + 1, what is the value of f(2)

Given f(t) = 3 r3 - 3r + 1, what is the value of f(2)
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Given f(t) = 3 r3 - 3r + 1, what is the value of f(2)

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User Arcord
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1 Answer

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Answer: f(2)=19

Explanation:

F(2) = 3(2)3 -3(2) + 1

F(2) = 24 - 6 + 1

F(2) = 19

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User Rodo
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