Question

HELP!!!!

(2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ (5^-2 / 2^3)^4 ⋅ 2^28
Write in the simplified form, and show steps, please!!!!

Answer 1

(2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ (5^-2/2^3)^4 ⋅ 2^28

= (2^-16 ⋅ 5^10 ⋅ 1)⋅(5^-8 / 2^12) ⋅ 2^28

= 2^(-16-12+28) ⋅ 5^(10-8)

= 2^0 ⋅ 5^2

= 1 ⋅ 25

= 25

Explanation: