Question

Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than Maria? (Show your work please!)

Answer 1

Given:

Atul has
`(2)/(3)` lb of candy.

Jose has
`(3)/(5)` lb of candy.

Maria has
`(1)/(2)` lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has
`(1)/(2)` lb less than Jose, therefore

Maria has =
`(3)/(5)-(1)/(2)` lb

Maria has =
`(6-5)/(10)` lb

Maria has =
`(1)/(10)` lb

Difference between the candies Atul and Maria have.

Difference =
`(2)/(3)-(1)/(10)` lb

Difference =
`(20-3)/(30)` lb

Difference =
`(17)/(30)` lb

Therefore, Atul have
`(17)/(30)` lb of candy more than Maria.