6. Un volumen de 1.0 mL de agua de mar contiene casi 4 x 10-12 g de Au. El volumen total de agua en los océanos es de 1.5 x 1021 L. Calcule la cantidad total de Au (en gramos) e…

Question

asked Jun 6, 2021 181k views

1 Answer

Itshorty · Answer 1 · 2021-06-11T04:40:25+0000

Answer:

The total amount of Au is $
2.0*10^(24)

Step-by-step explanation:

Given that,

Mass of 1.0 ml of Au
$m=4*10^(-2)\ g$

Total volume of water in oceans
$V=1.5*10^(21)\ L$

We need to calculate the volume in ml

Using given volume

$V=1.5*10^(21)*1000\ mL$

$V=1.5*10^(24)\ mL$

We need to calculate the total mass of Au

Using given data

$1\ ml\ volume = 4*10^(-2)\ g$

$1.5*10^(24)\ ml=4*10^(-2)*1.5*10^(24)$

So, The total mass of Au is
$6*10^(22)\ g$

The mass will be in ounce,

Mass=0.035274*6*10^(22)

$Mass=2.12*10^(21)\ ounce$

The total amount of the Au Will be

$Total\ amount=2.12*10^(21)*948$

$Total\ amount=2.0*10^(24)$

Hence, The total amount of Au is $
2.0*10^(24)