asked 98.2k views
4 votes
A rectangle has a perimeter of 48 inches. If twice the length decreased by three is equal to three times the width, the find the length and the width

asked
User Schmalls
by
8.5k points

2 Answers

1 vote
pretty sure the width would be 31
answered
User Paul Geisler
by
8.4k points
3 votes

Answer:

Length= 15, width= 9

Explanation:

perimeter of a rectangle P= 2(L+W)

L= length

W= width

48=2(L+W)---------------(1)

twice the length= 2×L= 3L

decreased by three= 2L-3

three times the width= 3×W= 3W

twice the length decreased by three is equal to three times the width

2L-3= 3W-------------------(2)

solving equation one and two simultaneously

from equation (2)

3W= 2L-3

W=2L/3-3/3

W= 2L/3 - 1----------(3)

substitute equation (3) into equation (1)

48=2(L+2L/3-1)

48=2L+4L/3-2

48×3=6L+4L-6

144=10L-6

10L=144+6

10L=150

dividing bothsides by 10

L= 15

substitute L= 15 into equation (2)

2L-3=3W

2(15)-3=3W

30-3 = 3W

27= 3W

3W= 27

dividing bothsides sides 3

3W=27/3

W=9

therefore, Length= 15, width= 9

answered
User Palak Bansal
by
8.0k points

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