Question

A given volume of methane diffuses in 20 seconds How long will it take the

same volume of sulphur (IV) oxide to
diffuse under the same condition
(Methane = 16, Sulphur (IV) oxide=64)​

Answer 1

Step-by-step explanation:

Relative molecular mass of CH4 = 12 * 1 + 4 = 16

Relative molecular mass of SO2 = 32 + 10 *2 = 64

tSO2/tCH4 = √MSO2/MCH4

t/20 = √64/16 = √4

t/20 = 2

∴ t = 20 * 2 = 40sec