Question

Find the value of k for which the point (1, -2) lies on the graph of the

linear equation x - 2y + k = 0.

Please answer with steps!
No wrong/spam answers!

Answer 1

k = - 5

Explanation:

Since point (1, - 2) lie on the line x - 2y + k = 0.

So, plug x = 1 & y = - 2 in the given equation of line, we find:

`1 - 2( - 2) + k = 0 \\ 1 + 4 + k = 0 \\ 5 + k = 0 \\ \implies \huge \purple{ \boxed{\: k = - 5}}`

Answer 2

k= -5

Explanation:

When x=1 and y= -2,

x-2y+k=0

1 -2(-2)+ k=0

1+4+k=0

5+k=0

k= -5