Question

Noel has a son and daughter who both play basketball. The probability his son will score more than 10 points in his game is 0.40. The probability that his daughter will score more than 10 points in her game is 0.50. Assume the probability of each scoring more than 10 points is independent from the other. What is the probability of ONLY his daughter scoring more than 10 points

Answer 1

P (B)= 0.5

Explanation:

Let A be the probability his son will score more than 10 points in his game then P (A)= 0.40.

Let B be the probability that his daughter will score more than 10 points in her game then P (B)= 0.50.

As the probability of each scoring more than 10 points is independent from the other. The probability of ONLY his daughter scoring more than 10 points

is given by

P (B)= P ( B/A) For independent events.

P (B/A)= P (B and A)/ P (A) = 0.5*0.4/0.4= 0.5

P (B)= 0.5