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At elevated temperatures, methylisonitrile (CH3NC) converts to acetonitrile (CH3CN): CH3NC(g) --> CH3CN(g) At the start of the experiment, there are 0.200 mol of reactant (CH3NC) and 0 mol of product (CH3CN) in the reaction vessel. After 25 min of reaction, 0.108 mol of reactant (CH3NC) remain. The average rate of decomposition of methyl isonitrile, CH3NC, in this 25 min period is __________ mol/min. A. 3.7 x 10-3 B. 0.092 C. 2.3 D. 4.3 x 10-3 E. 0.54

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User Jymdman
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1 Answer

6 votes

Answer:

A. 3.7 x 10⁻³

Step-by-step explanation:

In the beginning of the reaction there are 0.200 moles of reactant. After 25 minutes, remain 0.108 moles. That means the moles that wer descomposed are:

0.200 moles - 0.108 moles = 0.092 moles of reactant were descomposed.

That descomposition occurs in 25 minutes. The average rate of descomposition in moles / minute are:

0.092 moles Methyl isonitrile / 25 minutes = 3.7x10⁻³ mol/min.

Right option is:

A. 3.7 x 10⁻³

answered
User Rohit Pareek
by
8.1k points
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