A snowmobile has an initial velocity of +3.5 m/s. If it accelerates at the rate of +0.69 m/s^2 for 8.3 s, what is the final velocity? Answer in units of m/s.

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asked Apr 17, 2021 156k views

1 Answer

Electrobabe · Answer 1 · 2021-04-21T06:10:19+0000

This follows directly from the definition for average acceleration:

$a_(\rm ave)=(\Delta v)/(\Delta t)=\frac{v_f-v_i}t$

Under constant acceleration, acceleration and average acceleration are interchangeable. So we have

$0.69(\rm m)/(\mathrm s^2)=(v_f-3.5(\rm m)/(\rm s))/(8.3\,\mathrm s)$

$\implies v_f=3.5(\rm m)/(\rm s)+\left(0.69(\rm m)/(\mathrm s^2)\right)(8.3\,\mathrm s)$

$\implies\boxed{v_f=9.227(\rm m)/(\rm s)}$