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Given t(x)=-4.9t2+3t+10, what is the value of t(1)?

Given t(x)=-4.9t2+3t+10, what is the value of t(1)?
asked 116k views
1 vote
Given t(x)=-4.9t2+3t+10, what is the value of t(1)?

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User HcgRandon
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1 Answer

3 votes

Explanation:

t(x) = -4.9t² + 3t + 10

t(1) = -4.9(1²) + 3(1) + 10

= -4.9 + 3 + 10

= 8.1

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User Oktapodi
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