Question

Solve 6^x+2 = 10 for x using the change of base formula

Answer 1

`x\approx-0.7149`

Explanation:

`\displaystyle 6^(x+2)=10\\\\\log_6(6^(x+2))=\log_6(10)\\\\x+2=(\log(10))/(\log(6))\\\\x+2\approx1.2851\\\\x\approx-0.7149`

Recall that the change of base formula is
`\displaystyle \log_a(b)=(\log(b))/(\log(a))`