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C^1/2+c^1/3 for c=64

1 Answer

2 votes

Answer:

12

Explanation:


\huge {c}^{ (1)/(2) } + {c}^{ (1)/(3) } \\ \\ \huge = {64}^{ (1)/(2) } + {64}^{ (1)/(3) } \\(plug \: c = 64) \\ \\ \huge = { ({8}^(2)) }^{ (1)/(2) } + {( {4}^(3) )}^{ (1)/(3) } \\ \\ \huge = {8}^{2 * (1)/(2) } + {4}^{3 * (1)/(3) } \\ \\ \huge = 8 + 4 \\ \\ \huge = 12

answered
User Costantino Grana
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