Answer:
11, 43, 80
Explanation:
A second number is 10 more than three times a first number 
The third number is 14 more than six times the first number 
The sum of the three numbers is 134. What are the three 
numbers?
call the first number " x "
call the second number " y "
call the third number " z "
now represent the given information algebraically
y - 10 = 3x
manipulate for the problem:
y = 3x +10
z - 14 = 6x
manipulate for the problem:
z = 6x +14
x + y + z =134
now use substitution to form one equation
x + y + z = 134
x + 3x + 10 + 6x + 14 = 134
simplify and solve by inverse operations:
10x + 24 = 134
10x = 110
x = 11
now substitute back into to find the answer to the problem
y= 3x + 10
y = 3 * 11 +10
y = 43
z = 6x + 14
z = 6 * 11 + 14
z = 80