Question

Find the equation of the line that passes through the point (0,1) and is parallel to y=−25x+3.

Answer 1

y = -25x +1

Explanation:

`(0,1)=(x_1,y_1)\\\\y = -25x +3\\\\m = -25`

Substitute given values into point slope form

`y-y_1=m(x-x_1)\\\\y - 1 = -25(x -0)\\\\y-1 =-25x+0\\\\y =-25x+0+1\\\\y = -25x +1`