Question

Find the equation of the line perpendicular to x−5y=15 that passes through the point (−2,5).

Answer 1

Explanation:

-5y = -x + 15

5y = x - 15

y = 1/5x - 3

perp. -5

y - 5 = -5(x + 2)

y - 5 = -5x - 10

y = -5x - 5