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Identify the CENTER: (x+3)^2 + (y-2)^2 = 64 *
(3,-2)
(9,4)
(-3,2)
8

asked
User EMX
by
8.2k points

1 Answer

0 votes

Answer:

centre = (- 3, 2 )

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius )

(x + 3)² + (y - 2)² = 64 ← is in standard form

with centre (- 3, 2 )

answered
User Rahul Banerjee
by
7.9k points

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