The period, T, of a pendulum of length l is given by T = f(l) = 2π√l/g, where g is a constant. Find f^-1.

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asked Apr 24, 2021 203k views

1 Answer

Ashokbabuy · Answer 1 · 2021-04-27T18:36:20+0000

Answer:

When effective length (L) is constant, the time period (T) of oscillation of a simple pendulum is inversely proportional to the square root of the acceleration due to gravity (g) at a place of observation. So, T∝√1g when L is constant.

Explanation:

The period, T, of a pendulum of length l is given by T = f(l) = 2π√l/g, where g is a constant. Find f^-1.

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