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You do a pull-up, lifting yourself by 0.5 in 2 seconds. If your weight is 600 N, how much work did you do and what was your power output during lifting

1 Answer

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Answer:

1.) 15.24 J

2.) 7.62 W

Explanation:

Given that You do a pull-up, lifting yourself by 0.5 in 2 seconds. If your weight is 600 N,

Convert inches into metres

1 inches = 0.0254 metres

Work done = Force × distance

Work done = 600 × 0.0254

Work done = 15.24 J

Power is the rate at which work is done.

That is,

P = WD / time

Power = 15.24 / 2

Power = 7.62 W

Therefore, 15.24 Joule of work done must be done and 7.62 watt of power output must be required to lift the yourself.

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User Catcon
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