Question

You order 1.5 pounds of turkey at the deli. You will accept the turkey if its weight is between 1.54 and 1.46 pounds. What absolute value inequality can be used to describe the tolerance of the weight of the turkey?

Answer 1

The absolute value inequality that represents the tolerance of the weight of the turkey is |w - 1.5| ≤ 0.04, where 'w' is the actual weight of the turkey.

Step-by-step explanation:

To determine the absolute value inequality that represents the tolerance of the weight of the turkey, you first need to calculate the deviation from the mean weight that you would accept. The mean weight is 1.5 pounds, and you will accept a weight between 1.46 and 1.54 pounds. The absolute value inequality will express how far the weight can be from the mean on both the lower and upper sides.

The deviation on either side is 0.04 pounds (since 1.5 - 1.46 = 0.04 and 1.54 - 1.5 = 0.04). Therefore, the absolute value inequality is |w - 1.5| ≤ 0.04, where ‘w’ represents the weight of the turkey.

This inequality means that the acceptable weight of the turkey is within 0.04 pounds of 1.5 pounds, either above or below.