Question

HELP PLEASE 100 POINTS!!!!

Given JAM and segment PB such that PB JM, what is the missing justification in the proof that JP/PA = MB/BA

Answer 1

Answer: AA similarity posulate

Explanation:

In ΔAJM and ΔAPB,

∠PAB = ∠JAM,

Also, since PB || JM, the corresponding angles formed by these two parallel lines with the line AJ are equal i.e.

∠AJM = ∠APB

So, using the AA similarity postulate, we can say that ΔAJM is similar to ΔAPB