Question

19mg of 9-fluorenone is dissolved in 5ml of diethyl ether. The resulting organic solution is extracted with 10ml of water. The Kp for 9-fluorenone in diethyle ether/water is 9.5, how much would remian in the ether layer?

Answer 1

The value is
`z = 15.7 mg`

Step-by-step explanation:

From the question we are told that

The mass of 9-fluorenone is m = 19 mg

The volume of diethyl ether V = 5 ml

The volume of water is
`V_w = 10 ml`

The equilibrium constant for 9-fluorenone is
`K_p = 9.5`

Generally the equilibrium constant for 9-fluorenone is mathematically represented as

`K_p = ( (z )/(V) )/( (m - x )/(V_w) )`

Here z is the remaining mass of 9-fluorenone

=>
`9.5 = ( (z )/(5) )/( (19 - z )/( 10) )`

=>
`9.5 = (2z)/(19 - z)`

=>
`z =  15.7 mg`