Answer:
Δp = -2 p₀
Step-by-step explanation:
The momentum is defined by 
 p = m v 
In this case we write the initial and final momentum, we take as positive the direction towards the wall. 
 p₀ = m v 
 p_f = m (-v)
 
the negative sign is because the car is bouncing off the wall 
 
the change of the moment is 
 Δp = p_f - p₀ 
 Δp = - m v - m v 
 Δp = -2 mv 
 Δp = -2 p₀
 
we see that the change of moment is twice the moment, in the attachment we can see the vectors of these changes and the sign indicates the direction of the change at the moment