Question

Point J is on line segment IK. Given JK 2x – 1, IK = 3x + 2, and

IJ = 3x – 5, determine the numerical length of JK.

Answer 1

JK = 7

Explanation:

Point J is on line segment IK.

`\therefore JK + IJ = IK\\</p><p>\therefore 2x-1 + 3x - 5 = 3x + 2\\</p><p>\therefore 5x - 6 = 3x + 2\\</p><p>\therefore 5x - 3x = 2 + 6\\</p><p>\therefore 2x = 8 \\ \therefore x = (8)/(2) \\ \therefore x = 4 \\ \\ JK = 2x - 1 = 2 * 4 - 1 = 8 - 1 \\ \huge \red{ \boxed{JK = 7}}`