Question

Mrs. Pellegrin has weighed 5 packages of cheese and recorded the weights as 10.2 oz, 10.5 oz, 9.3 oz, 9.8 oz, and 10.0 oz. She calculated the standard deviation to be 0.45 oz. The cheese factory lists the package weight at 10 oz. t equals fraction numerator x with bar on top minus mu over denominator begin display style bevelled fraction numerator s over denominator square root of n end fraction end style end fraction The t-statistic for a two-sided test would be __________.

Answer 1

+.20 or -.20

Explanation:

Answer 2

Answer: - 0.20

Explanation:

Given the following :

Sample weights 10.2, 10.5, 9.3, 9.8, 10

Sample mean: ΣX / n

n = number of observations = 5

Sample mean (m)= (10.2+10.5+9.3+9.8+10) / 5= 49.8 / 5 = 9.96

Population mean (p) = 10.0

Standard deviation (sd) = 0.45

T statistic = (m - p) / sd/sqrt(n)

Tstatistic = (9.96 - 10) / 0.45÷sqrt(5)

= - 0.04 / 0.2012461

= - 0.1987

= - 0.20