asked 227k views
1 vote
What is the slope of a line perpendicular to the line whose equation is 3x-12y=2163x−12y=216.

2 Answers

3 votes

Answer:

Slope (m) = 3

Explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

answered
User Ian Ringrose
by
7.7k points
3 votes

Answer:

Deleted account

Explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

Explanation:

answered
User Grahesh Parkar
by
7.8k points

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