Question

Find cot B if csc ß= 3/5/5 and secß -3/2​

Answer 1

A)
`\displaystyle (2√(5))/(5)`

Explanation:

Since
`\csc\beta=(1)/(\sin\beta)`,
`\sec\beta=(1)/(\cos\beta)`, and
`\cot\beta=(\cos\beta)/(\sin\beta)`, then
`\cot\beta=(\csc\beta)/(\sec\beta)`

This means that
`\displaystyle \cot\beta=(-(3√(5))/(5))/(-(3)/(2))=(-3√(5))/(5)*-(2)/(3)=(2√(5))/(5)`