Answer:
Step-by-step explanation:
Initial relative velocity of the car = 0
relative acceleration = .65 m /s²
relative distance covered = 24.7 + 21.5 + 4.8 + 25.5 = 76.5 m 
Let time taken be t 
from the relation 
s = ut + 1/2 a t²
76.5 = 0 + .65/2 t²
t = 15.34 s 
actual distance covered by car during this period 
s = ut + 1/2 a t²
= 20.3 x 15.34 + 1/2 x .65 x 15.34²
= 311.4 +76.47
= 387.87
C )
v = u + at 
= 20.3 + .65 x 15.34 
= 30.27 m /s