Answer:
33 math problems
Explanation:
Let's set a few variables:
Number of math problems = m
Number of history problems = h
We know that in total, we have 42 problems.
m + h = 42
We also know that our math homework has 6 problems more than 3 times the number of history problems.
m = 3*h + 6
So m is 3 times h, plus 6.
m + h = 42
We can subtract h from both sides of this equation.
m = 42 - h
Now we can put this value for m, 42-h, into our other equation.
m = 3*h + 6
42 - h = 3*h + 6
Subtracting 6 from both sideS:
36 - h = 3*h
Adding h to both sides:
36 = 3*h + h
36 = 4*h
Dividing both sides by 4:
9 = h
h = 9
We know that the number of math problems is the following:
m = 42 - h
Let's put the value for h, 9, into this equation:
m = 42 - 9
m = 33
Answer: 33 math problems