asked 212k views
1 vote
a football was kicked vertically upward from a height of 4 feet with an initial speed of 65 feet per second. the formula h=4+65t-16t^2 describes the balls height above ground, h, in feet, t seconds after it was kicked. Use the formula to find the ball's height 2 seconds after it was kicked.

asked
User Tjeden
by
7.3k points

1 Answer

6 votes

Answer:

70 feet

Explanation:

Given


h=4+65t-16t^2

Required

Determine h when t = 2

Substitute 2 for t in the given equation


h=4+65 * 2-16* 2^2

Solve all exponents


h=4+65 * 2-16* 4


h=4+130-64


h=70

answered
User Jeet
by
9.0k points
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