Question

Can someone help me with 5 and 6?

Answer 1

5.

`\left(8-6\right)^5\cdot \:2^(-4)+2^0`

Subtract 8 - 6 = 2:

`(2)^5\cdot \:2^(-4)+2^0`

Anything to the power of 0 is 1. (Except 0):

`2^5\cdot \:2^(-4)+1`

Multiply:

`2^(5-4)+1`

`2^1+1`

`2+1`

`3`

6.

`(\left(9-1\right)^5)/(\left(6+2\right)^3)`

Solve the brackets: 9 - 1 = 8 and 6 + 2 = 8:

`(8^5)/(8^3)`

`8^(5-3)`

`8^2`

(or
`64` for exact value)