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Lead (Pb) (average atomic mass 207.19 amu) has three naturally-occurring isotopes, Pb206, Pb207and Pb208 with isotopic masses of 205.98 amu, 206.98 amu and 207.98 amu respectively. If the isotopes Pb207and Pb208 are present in equal amounts, calculate the percent abundance of each isotope of Pb, which are, Pb206, Pb207 and Pb208.​

asked
User Leoh
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8.2k points

1 Answer

1 vote

Answer:

pb am 207.19 amu

pb206, pb207and pb208

answered
User Godaygo
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8.0k points
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