Question

How long should a spring be stretched for it to store 45 J of energy? The force constant of the spring is

540N/m?

Answer 1

x = 0.4 m

Step-by-step explanation:

When a spring is stretched from its equilibrium position. Some energy is stored in the spring. This energy is called the elastic potential energy of the spring. The formula used to calculate the magnitude of this stored energy is given as follows:

P.E = (1/2)kx²

where,

P.E = Elastic Potential Energy Stored in the spring = 45 J

k = Spring Constant = 540 N/m

x = amount of stretching = ?

Therefore,

45 J = (1/2)(540 N/m)x²

x² = (45 J)(2)/(540 N/m)

x = √(0.167 m²)

x = 0.4 m