Question

(u+v)*2+2(u+v)-3
factorise it completely
it's a challenge


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Answer 1

If you mean

`(u+v)^2+2(u+v)-3`

you can first substitute
`x=u+v` to get

`x^2+2x-3=(x+3)(x-1)`

and so

`(u+v)^2+2(u+v)-3=\boxed{(u+v+3)(u+v-1)}`