Find the sum of the following geometric sequences. d) 3 terms a= 16 r=3/4

Question

asked Jun 24, 2023 24.5k views

1 Answer

Smukamuka · Answer 1 · 2023-06-29T20:52:32+0000

Answer:

S₃ = 37

Explanation:

given a₁ = 16 and r =
(3)/(4) , then

a₂ = a₁ ×
(3)/(4) = 16 ×
(3)/(4) = 12

a₃ = a₂ ×
(3)/(4) = 12 ×
(3)/(4) = 9

then

S₃ = a₁ + a₂ + a₃ = 16 + 12 + 9 = 37