asked 96.8k views
2 votes
3a+2b+cx=2(4d-5e) how do i find x?

2 Answers

3 votes
I hope the image helps. I hope u see it but anyways x = -3a-2b+8d-10e/c
3a+2b+cx=2(4d-5e) how do i find x?-example-1
answered
User Kolinko
by
7.9k points
4 votes

Answer:


x = (8d-10e-3a-2b)/(c)

Explanation:

In order to find x, our goal is to isolate it on one side of the equation.

To do this, let's first apply the distributive property on the right side of the equation.


3a+2b+cx = 8d - 10e

Now we can subtract
3a and
2b from both sides:


cx = 8d - 10e - 3a - 2b

And now we can divide both sides by
c so that x is alone on the left side.


x = (8d-10e-3a-2b)/(c)

Hope this helped!

answered
User Aryan Pandhare
by
7.8k points
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