Question

What is the length of the given segments EF and GH?

Answer 1

`EF = 5`

`GH = 5`

Explanation:

Length of EFis the distance between E(-4, -3) and F (-1, 1).

`EF = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

Let,

`E(-4, -3) = (x_1, y_1)`

`F(-1, 1) = (x_2, y_2)`

`EF = √((-1 -(-4))^2 + (1 -(-3))^2)`

`EF = √((3)^2 + (4)^2)`

`EF = √(9 + 16) = √(25)`

`EF = 5`

Distance between G(-2, -3) and H(3, -3)

`GH = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

Let,

`G(-2, -3) = (x_1, y_1)`

`H(3, -3) = (x_2, y_2)`

`GH = √((3 -(-2))^2 + (-3 -(-3))^2)`

`GH = √((5)^2 + (0)^2)`

`GH = √(25 + 0) = √(25)`

`GH = 5`