Question

1s22s22px22py22pz23s23px23py23pz2

Answer 1

Given :

Electronic configuration of an electron :

`1s^2\ 2s^2\ 2p_x^2\ 2p_y^2\ 2p_z^2\ 3s^2 \ 3p_x^2\ 3p_y^2\ 3p_z^2` .

To Find :

The element having such an electronic configuration .

Solution :

We know , the sum of all the power of s and p in all the orbit gives total number of atoms in elements .

So , atomic number is :

`Z=2+2+(2+2+2)+2+(2+2+2)\\\\Z=18`

Since , the atomic number is 18 .

Therefore , the element is Argon .

Hence , this is the required solution .