Question

Write the following equation in standard form. Then solve. 6q^2-4q=5q^2-6q+48

Answer 1

q = -8, q = 6

Explanation:

`6 {q}^(2) - 4q = 5 {q}^(2) - 6q + 48`

Move everything to the left of the =:

`6 {q}^(2) - 4q - 5 {q}^(2) + 6q - 48 = 0`

Combine terms with the same power of q:

`{q}^(2) + 2q - 48 = 0`

Now you need to find two numbers that multiply to make -48 and add to make 2.

The numbers I found are 8 and -6.

Then write two parentheses like this:

`(q + 8)(q - 6) = 0`

Then you need to look at each parenthesis individually. See what q would have to be for the parenthesis to equal 0.

For the the first one, q would have to be -8

For the second one, q would have to be 6

These are the solutions for q.