Question

Identify the zeros of the function f(x) = x2 + 16.

Answer 1

no real zeros

imaginary zeros : ±4i

Explanation:

f(x) = x^2 + 16

Set equal to zero

0 = x^2 +16

Subtract 16 from each side

-16 = x^2

We have no real zeros

We have imaginary zeros

Taking the square root of each side

sqrt(-16) = sqrt(x^2)

±4i = x