Question

Find the value of p so that the quadratic solution x(2 x+p) + 8 = 0 has real and distinct roots

Answer 1

p = -17, x = 8

p = -10, x = 1

p = -10, x = 4

p = 10, x = -1

Step by Step:

x (2 x + p) + 8 = 0

x = 1/4 (-sqrt(p^2 - 64) - p)

Hope I helped!