Question

R.1 Trigonometric ratios: sin, cos and tan
Find the sine of D.

Answer 1

Below.

Explanation:

Using Pythagoras theorem:

(√69)^2 = (√47)^2 + BC^2

BC^2 = 69-47 = 22

BC = √22.

sin D = BC / CD

= √22/√69

= 0.5647 to nearest ten thousandth.