Question

A car has a velocity of 6.23 m/s. The driver hits the gas and accelerates the car at 2.16 m/s^2. How fast is the car moving after 5.85 s?

Answer 1

Recall that

`v_f=v_i+at`

So we have

`v_f=6.23(\rm m)/(\rm s)+\left(2.16(\rm m)/(\mathrm s^2)\right)(5.85\,\mathrm s)`

`\implies\boxed{v_f\approx18.9(\rm m)/(\rm s)}`