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A 7.52nC charge is located 1.65m from a 4.10nC point charge.a) Find the magnitude of the force that the -2.5 nC charge exerts on the -8.0 nC charge.b) Is the force attractive or repulsive?

1 Answer

5 votes

Answer:

a.
1.019 * 10^(-7) N

b. Repulsive force

Step-by-step explanation:

The computation is shown below:

a. The magnitude of the force is

Given that

Charge = 7.52nc

Location = 1.65m

Point charge = 4.10nC

Based on the above information,

As we know that


F= (kqQ)/(r^2) \\\\= (9*10^(9) * 7.52 * 10^(-9) * 4.1 * 10^(-9))/(1.652) \\\\= 1.019 * 10^(-7) N

b. Now as it can be seen that both contains the positive charges so this represents the repulsive force and the same is to be considered

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User Kampageddon
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