Question

PLEASE HELP ASAP!!!!

Which statement describes the symmetry of j(x)?

j(x) is an odd function.
j(x) is an even function.
j(x) is both an even and an odd function.
j(x) is neither an even nor an odd function.

Answer 1

A) j(x) is an odd function.

Explanation:

Answer 2

j(x) is an odd function

Explanation:

We are given;

j(x) = 220/x³ and j(-x) = 220/(-x)³

Now,

when x = 1;

j(x) = 220/1³ = 220/1 = 220

j(-x) = 220/(-1)³ = 220/-1 = -220

When x = 2;

j(2) = 220/2³ = 220/8

j(-2) = 220/(-2)³ = -220/8

Now, Algebraically, function j would be even if and only if j(-x) = j(x) for all x in the domain of j. While j is odd if and only if j(-x) = -j(x) for all x in the domain of j.

From the values gotten, we can see that :j(-x) = -j(x). Thus, we can say that j(x) is an odd function.